Tuesday, September 18, 2012

Normality Calculation Based on Concentration

For calculation of Normality in Liquid (Acids) is Based on three factors:

1. Specific Gravity of the substance.   
2. Equivalent Weight of the substance.
3. Puirity of the substance.

For eg:  Calculation of Hydrochloric Acid Normality:

Sp. Gravity of HCl   =  1.18; Equivalent weight     =  36.45; Purity of HCl           =  35%

                                            Specific Gravity of HCl   x Purity of HCl x 1000
Normality of HCl     =        _____________________________________
                                           Equivalent weight of HCl  x   100

                                                    1.18   x  35 x  1000
Normality of HCl     =         ______________________
                                            36.45     x  100

                                                    1.18  x 35 x 10
Normality of HCl    =         ________________
                                                   36.45

Normality of HCl    = 11.3 N

Calculation of Sulphuric Acid Normality:


Sp. Gravity of H2SO4 = 1.84 ; Equivalent weight = 49.04 ; Purity of H2SO4 = 98%


                                        Specific Gravity of H2SO4 x Purity of H2SO4 x 1000
Normality of H2SO4 = _____________________________________

                                    Equivalent weight of H2SO4 x  100

                                                        1.84 x 98 x 1000
Normality of H2SO4 =           ______________________

                                                  49.04 x  100

Normality of H2SO4  =  36.8 N


Calculation of Nitric Acid Normality:


Sp. Gravity of H2SO4 = 1.42; Equivalent weight = 63; Purity of H2SO4 = 70%

                                          Specific Gravity of HNO3 x Purity of HNO3 x 1000
Normality of HNO3 = _____________________________________

                                           Equivalent weight of HNO3 x  100

                                                  1.42 x 70 x 1000
Normality of HNO3 =    ______________________

                                                63 x 100

Normality of Nitric Acd  =  15.8 N

55 comments:

  1. your calculation is wrong.....how you calculate ??? dont make fool...

    ReplyDelete
    Replies
    1. for liquUid N= DENSITY*PURITY*1000/EQUIVALENT WT*100

      Delete
    2. Can anyone tell me the formula of normality calculation for solid substance like NaoH???

      Delete
    3. W=NVE/1000..
      N=normality need
      V=req volume..
      E=equivalent weight.



      Delete
    4. N = ENV/1000 this formula used for solid chemicals Determination of normality for 1000 ml value
      and this for liquid Normality = Specific gravity X Purity X 1000/Equivalent weight X 100
      if want to make N from the known value use formula N1*V1=N2*V2

      Delete
  2. Actually Normality = Specific gravity X Purity X 1000/Equivalent weight X 100

    ReplyDelete
    Replies
    1. this formula is correct. it gives the correct answer ... previous formula is wrong

      Delete
    2. That exact equation he used here, gives the same result

      Delete
    3. Normality=wt×1000/GEwt× vol in ml but this is not considered

      Delete
    4. 100 means, in this normality formula

      Delete
  3. yes it is wrong calculation

    ReplyDelete
  4. Absolutely wrong,,,,,Mr.selvan's formula s right

    ReplyDelete
  5. Mr.selvan's formula is right.......

    ReplyDelete
  6. how we will caculate 0.3 normal solution of hcl

    ReplyDelete
    Replies
    1. Ml HCl(32%) to use = ( molec wt × N required)/basicity×%purity×1.18
      Specific gravity hcl =1.18

      Delete
  7. 26.48mL of 35% Hcl in 1000 ml gives you 0.3 Normal.

    ReplyDelete
    Replies
    1. how i will prepare 2 normality solution of hcl ? who the above things we find?

      Delete
    2. how i will prepare 2 normality solution of hcl ? who the above things we find?

      Delete
    3. Try formuyla N1V1 = N2V2
      where N1=Normality of solution u have (Std Normality of Conc. HCL, 11.3N)
      N2 = Normality of solution you want to prepare (here, 2N)
      V1 = Volume of solution (Here Conc. HCL) u should take which u need to find out and
      V2 = Volume of solution you want to prepare.

      Delete
    4. Try formuyla N1V1 = N2V2
      where N1=Normality of solution u have (Std Normality of Conc. HCL, 11.3N)
      N2 = Normality of solution you want to prepare (here, 2N)
      V1 = Volume of solution (Here Conc. HCL) u should take which u need to find out and
      V2 = Volume of solution you want to prepare.

      Delete
  8. N1*V1 = N2*V2 formula to be used for converting (diluting)solution normality.

    ReplyDelete
  9. can anyone tell me the reason why we are multiplying 1000 to get the normality?

    ReplyDelete
    Replies
    1. 1000 means the volume of 1 litre solution expressed in ml

      Delete
  10. Why we use 1000/100 for what purpose

    ReplyDelete
    Replies
    1. 1000 is used to express for 1 litre in ml and 100 is taken down from the percentafge purity because 35 % Hcl means 35/100

      Delete
  11. I want to understand polar and non polar drug and solvent

    ReplyDelete
  12. I want to understand polar and non polar drug and solvent

    ReplyDelete
  13. M/5 H2SO4 ki normality ki valua kitni hogi.

    ReplyDelete
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  15. pls normality of 0.1HCL is what?

    ReplyDelete
  16. How is this formula derived from N1V1=N2V2

    ReplyDelete
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    ReplyDelete
  18. I want to know about traceable standards.

    ReplyDelete
  19. How make 1 Normality Dil.H2SO4(Sp.Gravity) and how can standardize.

    ReplyDelete
  20. How can we know the purity of an unknown acid

    ReplyDelete
  21. How can we know the purity of an unknown acid

    ReplyDelete
  22. How can make 1 Normality Dil.H2SO4(Sp.Gravity 1.84
    )

    ReplyDelete
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  24. hi any one tell me the calculation of different normality solution like 0.1 ,0.02 etc from 98% sulfuric acid

    ReplyDelete
    Replies
    1. Volume of acid(h2so4) in ml=0.5435×normality required
      Say .02 N H2SO4 uses
      .5435×.02= 1.09 ml of acid to be added to 1000 ml d/water make up vol

      Delete
  25. Why did we multiply by 1000 and divide by 100?

    ReplyDelete
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